16 Calculaţi:
a (2√5-√2)+(2+√10)-(3-√3-5)(3√3-5); (2√2-3√3)+2(√3+3√2)-12-(5√2-1)(5√2-1); c (3√7-1)-(3-√7)-(5-3√7)(2√7+3)-4(20-3√7); (√2+3√3)-(3√2-√3)(√5-2)(√5+2): + 2√5 [(√5-2) + 3(√5-1)-6( √5 +1); d e (4√3-1)(√3-3)+3√3-4)]-(3-√3); 8 3√5-10√5-3√5-(2-√5)-3(3-√5)]}
