[tex]\it \sqrt{\dfrac{35-x}{23+x}}\geq0 \Rightarrow \dfrac{35-x}{23+x}\geq0|_{+1} \Rightarrow\dfrac{35-x+23+x}{23+x}\geq1\Rightarrow \dfrac{58}{23+x}\geq1 \Rightarrow\\ \\ \\ \Rightarrow \begin{cases} \it 23+x\leq58|_{+23} \Rightarrow x\leq 35\ \ \ \ \ (1)\\ \\ \it 23+x>0 \Rightarrow x>-23\ \ \ \ \ \ \ \ (2)\end{cases}\\ \\ \\ (1),\ (2) \stackrel{x\in\mathbb{Z}}{\Longrightarrow}\ x\in\{-22,\ \ -21,\ \ -20,\ ...-2,\ \ -1,\ \ 0,\ \ 1,\ \ 2,\ \ 3,\ \ ...\ , \ 35 \}\ \ \ \ Suma\ \ este:\\ \\ S=23+24+25+\ ...\ +35=[/tex]...
