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Rombul ABCD, CU AC BD = {0} are soc = 108 em”. Ştiind ca BD = 0 calculati: a) aria rombului; b) lungimea diagonalelor BD şi AC​

Răspuns :

a)
Aromb=4×A(BOC)=4×108 cm²=432 cm²

b)
BD=3AC/8
Aromb=AC×BD/2=(AC×3AC/8) /2=3AC²/16
3AC²/16=432
AC²=432×16/3=144×16
√AC²=√(144×16)=12×4=48 cm
BD=3AC/8=3×48/8=3×6=18 cm