Răspuns: [tex]\bf \red{\underline{~50~}}[/tex]
Explicație pas cu pas:
[tex]\bf 2+4+6+.......+100-(1+3+5....+99)=[/tex]
[tex]\bf \{(2+100)\cdot[(100-2):2+1]:2\}-\{(1+99)\cdot[(99-1):2+1]:2\}=[/tex]
[tex]\bf [102\cdot(98:2+1):2]-[100\cdot(98:2+1):2]=[/tex]
[tex]\bf [102\cdot(49+1):2]-[100\cdot(49:2+1):2]=[/tex]
[tex]\bf (102\cdot50:2)-(100\cdot50:2)=[/tex]
[tex]\bf (51\cdot50)-(50\cdot50)=[/tex]
[tex]\bf 51\cdot50-50\cdot50=[/tex]
[tex]\bf 50\cdot(51-50)=[/tex]
[tex]\bf 50 \cdot 1 =\red{\underline{~50~}}[/tex]
Mai multe exemple de calcul a unor astfel de sume ai aici
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Bafta multa !
