v= d/t
(distanta supra timp)
t=10 min =10:60h=1/6h
[tex] \bf\green{v = \frac{d}{t} }= \frac{54}{10} km \div \frac{1}{6} h \\ \\ \bf \: v = \frac{54}{10} km \times \frac{6}{1} \\ \\ \bf \: v = \frac{324km}{10h} \\ \\ \boxed{ \bf \: v = 32.4 \frac{km}{h} }[/tex]