dau coroana detaliat va rog

Explicație pas cu pas:
[tex] \bf \bigg( \dfrac{2}{5} \bigg)^{34}: \bigg( \dfrac{2}{5} \bigg)^{14} =\bigg( \dfrac{2}{5} \bigg)^{34 - 14}=\red{\bigg( \dfrac{2}{5} \bigg)^{20}}[/tex]
___________________________
[tex]\bf \bigg[\bigg( \dfrac{2}{7} \bigg)^{3}\bigg]^{11} = \bigg( \dfrac{2}{7} \bigg)^{3 \cdot11}=\purple{\bigg( \dfrac{2}{7} \bigg)^{33}}[/tex]
==pav38==