Răspuns:
Explicație pas cu pas:
Ne folosim de limita remarcabila [tex]\lim_{x \to \inft0} (\frac{tgu(x) }{u(x) })=1[/tex]
[tex]\lim_{x \to \inft0} \frac{tg^{2}2x }{2x^{2} } = \lim_{x \to \inft0} (\frac{tg2x }{2x })^{2}\cdot2 =1\cdot 2=2[/tex]
[tex]\lim_{x \to \inft0} \frac{log_{2}(1-3x)}{4x} = \lim_{x \to \inft0} \frac{log_{2}(1-+(-3x))}{-3x} \cdot (-\frac{3}{4}) =1\cdot(\frac{-3}{4})=-\frac{3}{4}[/tex]
