Răspuns:
Explicație pas cu pas:
[tex]h=\frac{cateta1\cdot cateta2}{ipotenuza}[/tex]
[tex]h=\frac{(x+5)(x-2)}{x+7}[/tex]
(x+5)²+(x-2)²=(x+7)²
x²+10x+25+x²-4x+4=x²+14x+49
x²-8x-20=0
Δ=64+80=144
[tex]x_{1}=\frac{8+12}{2} =10\\x_{2}=\frac{8-12}{2} =-2<2 \ nu[/tex]
[tex]h=\frac{(x+5)(x-2)}{x+7}=\frac{15\cdot 8}{17} =\frac{120}{17}[/tex]
