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VA ROOOG! AM NEVOIE DE REZOLVAREA PROBLEMEI!!!​

VA ROOOG AM NEVOIE DE REZOLVAREA PROBLEMEI class=

Răspuns :

Răspuns:

Explicație pas cu pas:

daca grupa primul cu ultimul, urmatorul cu penultimul si tot asa  obtinem

[tex]\frac{1}{1521} +\frac{1}{2020} +\frac{1}{1522}+\frac{1}{2019} +...[/tex]

avem 500 termeni deci 250 de grupe

fiecare grupa va fi astfel

[tex]\frac{1}{1521} +\frac{1}{2020} \geq \frac{4}{3541} \\\\\frac{1}{1522}+\frac{1}{2019} \geq \frac{4}{3541}\\....[/tex]

deci daca adunam vom avea

[tex]\frac{1}{1521} +\frac{1}{2020} +\frac{1}{1522}+\frac{1}{2019} +...\geq 250 \cdot \frac{4}{3541}\\\\\frac{1}{1521} +\frac{1}{2020} +\frac{1}{1522}+\frac{1}{2019} +...\geq \frac{1000}{3541}[/tex]

[tex]\frac{1000}{3541} =0,28>\frac{1}{4}[/tex]

Deci

[tex]\frac{1}{1521} +\frac{1}{2020} +\frac{1}{1522}+\frac{1}{2019} +...>\frac{1}{4}[/tex]