5. Scrieți, folosind o singură putere:

Răspuns:
Explicație pas cu pas:
a)
= (3/2)⁵⁺⁷
= (3/2)¹²
-
b)
=(4/10)³⁺⁵
= (4/10)⁸
-
c)
2 ⁹/₇=(2*7+9)/7 =(14+9)/7=23/7
=(23/7)³⁺¹⁵
= (23/7)¹⁸
-
d)
= (15/90)³⁺⁴
=(15/90)⁷
-
e)
=(5/7)³⁻²
= (5/7)¹
-
f)
=(125/100)⁴⁺²
= (125/100)⁶
-
g)
7¹¹/₉₀= (7*90+11)/90= (630+11)/90=643/90
=( 643/90)³ˣ²
= (643/90)⁶
-
h)
=1 ...............orice nr ridicat la puterea 0= 1
Răspuns:
[tex]a)( \frac{3}{2} ) {}^{5} \times (\frac{3}{2} ) {}^{7} = ( \frac{3}{2} ) {}^{5 + 7} = ( \frac{3}{2} ) {}^{12} \\ b)( \frac{4}{10} ) {}^{3} \times ( \frac{4}{10} ) {}^{5} = ( \frac{4}{10} ) {}^{3 + 5} = ( \frac{4}{10} ) {}^{8} \\ c)(2 \frac{9}{7} ) {}^{3} \times (2 \frac{9}{7} ) {}^{15} = (2 \frac{9}{7} ) {}^{3 + 15} = (2 \frac{9}{7}) {}^{18} \\ d)( \frac{15}{90} ) {}^{3} \times (\frac{15}{90} ) {}^{4} = ( \frac{15}{90} ) {}^{3 + 4} = ( \frac{15}{90} ) {}^{7} \\ e) (\frac{5}{7} ) {}^{3} \div ( \frac{5}{7} ) {}^{2} = ( \frac{5}{7} ) {}^{3 - 2} = ( \frac{5}{7} ) {}^{1} = \frac{5}{7} \\ f)( \frac{125}{100} ) {}^{4} \times ( \frac{125}{100} ) {}^{2} = ( \frac{125}{100} ) {}^{4 + 2} = ( \frac{125}{100} ) {}^{6} \\ g)[(7 \frac{11}{90} ) {}^{3} ] {}^{2} = (7 \frac{11}{90} ) {}^{3 \times 2} = (7 \frac{11}{90} ) {}^{6} \\ h)[( \frac{2}{10} ) {}^{3} ] {}^{0} = ( \frac{2}{10} ) {}^{3 \times 0} = ( \frac{2}{10} ) {}^{0} = 1[/tex]
sper că te-am ajutat