[tex]v1 = 12ms = 43.2km \: h \\ a = \frac{v2 - v1}{t} = \frac{54 - 43.2 \:km \: h}{0.5s} = \frac{10.8km \: h}{0.5s} \\ = \frac{10.8 \frac{1000m}{3600s} }{0.5s} = \frac{ \frac{10.8}{3.6}m \: s }{0.5} = \frac{10.8}{1.8} m \: {s}^{2} = 6m \: {s}^{2} [/tex]
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succes
