Răspuns:
[tex] \bf \dfrac{12}{25}: 1\dfrac{3}{5} + \dfrac{9}{35}: \dfrac{3}{14} = [/tex]
[tex]\bf \dfrac{12}{25}:\dfrac{1 \cdot5 + 3}{5} + \dfrac{9}{35} \cdot \dfrac{14}{3} = [/tex]
[tex]\bf \dfrac{12}{25}:\dfrac{8}{5} + \dfrac{ \not9}{\not35} \cdot \dfrac{\not14}{ \not3} = [/tex]
[tex]\bf \dfrac{ \not12}{ \not25} \cdot\dfrac{ \not5}{ \not8} + \dfrac{ 3}{5} \cdot \dfrac{2}{ 1} = [/tex]
[tex]\bf \dfrac{ 3}{5} \cdot\dfrac{ 1}{2} + \dfrac{ 6}{ 5} =\dfrac{ 3}{10}+ \dfrac{^{2)}6}{ 5} = \dfrac{3 + 12}{10} = [/tex]
[tex]\bf \dfrac{15^{(5} \: }{10} = \red{ \boxed{ \dfrac{3}{2} }}[/tex]
==pav38==
