ms= 280 g , w%= 90%
w%= mdx100/ms => md= msxw%/100 = 280x90/100= 252 g HNO3
90 g 252 g md
C3H8O3 + 3HONO2 --> C3H5(ONO2)3 + 3H2O
92 3x63 227
=> C3H5O3 = 90/92 = 0,98
=> HNO3= 252/3x63 = 1,33
=> HNO3 este in exces iar calculele se vor face fata de glicerol
=> md= 90x227/92 = 222 g trinitrat
ms= mdx100/w% = 222x100/1 = 22200 g sol. de trinitrat