Răspuns:
Explicație:
[tex]\bf 0,8 \cdot 1,(6)=\dfrac{8^{(2}}{10} \cdot\dfrac{16-1}{9} =\dfrac{4}{\not5} \cdot\dfrac{\not15}{9} =\dfrac{4}{1} \cdot\dfrac{3^{(3}}{9} =[/tex]
[tex]\bf \dfrac{4}{1} \cdot\dfrac{1}{3} =\red{\boxed{\bf \dfrac{4}{3} }}[/tex]