plss repede dau coroana :g și i" metoda mersului invers plss

g)6+[15-(8:ax7+7)]x5=8:(1x4)+3x3
6+[15-(8:ax7+7)]x5=8:4+9
6+[15-(8:ax7+7)]x5=2+9
6+[15-(8:ax7+7)]x5=11
[15-(8:ax7+7)]x5=11-6 [15-(8:ax7+7)]x5=5
[15-(8:ax7+7)]=5:5 15-(8:ax7+7)=1
(8:ax7+7)=15-1
8:ax7+7=14 8:ax7=14-7
8:ax7=7
8:a=7:7
8:a=1
a=8
i) [(6*137-364:i):7+139]:3=834-751 [(6*137-364:1):7+139]:3=83
(6*137-364:1):7+139=83*3
(6*137-364:1):7+139=249 (6*137-364:i):7=249-139
(6*137-364:1):7=110 6*137-364:i=110*7
6*137-364:i=770
822-364:1-770
364:1-822-770
364:1-52
i=364:52
i=7