Răspuns:
a < b
Explicație pas cu pas:
[tex]a = {2}^{96} - {2}^{95} - {2}^{94} = {2}^{94}( {2}^{2} - 2 - 1) = {2}^{94} \times 1 = {2}^{94} = 2 \times {2}^{93} = 2 \times {2}^{3 \times 31} = 2 \times {( {2}^{3}) }^{31} [/tex]
[tex]b = {3}^{63} - {9}^{31} = {3}^{63} - {( {3}^{2}) }^{31} = {3}^{63} - {3}^{62} = {3}^{62} (3 - 1) = 2 \times {3}^{62} = 2 \times {3}^{2 \times 31} = 2 \times {( {3}^{2} )}^{31} [/tex]
[tex]2 \times {8 }^{31} < 2 \times {9}^{31} = > a < b[/tex]
