Răspuns:
MC34 H32 FeN4 O4=34x12+1x32+ 56+4x14+4x16=616g/mol
616g C34H32FeN4O......408gC.........32gH....56gFe.....56gN....64gO
100g C34H32FeN4O.....x%C................y%H......z%Fe........a%N.......b%O
x=100x408/616=calculeaza
y=100x32/616=calculeaza
z=100x56/616=calculeaza
a=100x56/616=calculeaza
b=100x64/616=calculeaza
Explicație: