Explicație pas cu pas:
[tex]log_{3}(8)\times log_{\sqrt{2} }(3) = log_{3}( {2}^{3}) \times log_{ {2}^{ \frac{1}{2}}}(3) = 3 log_{3}(2) \times \frac{1}{ \frac{1}{2} } log_{2}(3) = 3 log_{3}(2) \times 2log_{2}(3) =6 (log_{3}(2) \times log_{2}(3))= 6 \times 1 = 6 = ( \sqrt{6} )^{2} [/tex]
[tex] = > \sqrt{6} = \sqrt{log_{3}(8)\times log_{\sqrt{2} }(3)} [/tex]
