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aratati ca numarul A este natural: A=(8√3+14√3-12√3:)√75​

Răspuns :

rad75 = 5rad3
8rad3 : 5rad3=8/5
14rad3 : 5rad3=14/5
12rad3: 5rad3=12/5

A=8/5 + 14/5 - 12/5
A=10/5=2€N

[tex]\it A=10\sqrt3:\sqrt{75} =\dfrac{10\sqrt3}{\sqrt{75}}=\dfrac{10\sqrt3}{\sqrt3\cdot\sqrt{25}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2\in\mathbb{N}[/tex]