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[tex]3 \times - 1^{x + 2} + 4 \times { - 1}^{2x + 1} - 5[/tex]
Va rog!! Urgent!!​


Răspuns :

[tex]3 \times {(-1)}^{x + 2} + 4 \times { (- 1)}^{2x + 1} - 5 = \\ \\ = 3 \times {(-1)}^{x} \times {(-1)}^{2} + 4 \times {(-1)}^{2x}\times {(-1)}^{1}-5=[/tex]

[tex]=3 \times ( - 1) {}^{x} \times 1 + 4 \times 1 {}^{2x} \times ( - 1) -5= \\ \\ = 3 \times (- 1 {}^{x} ) + 4 \times 1 \times (-1) -5 \\ \\ = 3 \times ( - 1) {}^{x} - 4 -5=[/tex]

[tex] = 3 \times ( - 1) {}^{x} - 9[/tex]

  • dacă x număr PAR

[tex] = 3 \times 1 - 9 = 3 - 9 = - 6[/tex]

  • dacă x număr IMPAR

[tex] = 3 \times ( - 1) - 9 = - 3 - 9= - 12[/tex]