Explicație pas cu pas:
a)
[tex]| \sqrt{27} - 6| = |\sqrt{27} - \sqrt{36} | \\ \sqrt{27} < \sqrt{36} \\ \implies | \sqrt{27} - 6| = - (\sqrt{27} - \sqrt{36}) = \\ = \sqrt{36} - \sqrt{27} = 6 - \sqrt{27} \\ [/tex]
b)
[tex]a = \sqrt{12} - \sqrt{ {( - 3)}^{2} } + |1 + \sqrt{3} | + | \sqrt{27} - 6| - { | - \sqrt{2} | }^{2} = 2 \sqrt{3} - 3 + 1 + \sqrt{3} + 6 - 3 \sqrt{3} - 2 = 3 \sqrt{3} - 3 \sqrt{3} + 7 - 2 = 5[/tex]
