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Determinați numerele naturale n care verifica relatiile:a) 1pe3<n pe12<3pe4;b)1pe9<1pe2n+1<1

Dau coroana

Ajutoooor


Răspuns :

Hei! :)

a) [tex]\frac{1}{3} < \frac{n}{12} = > 12 < 3n = > 4 < n[/tex]  => n∈{5, 6, 7, 8, .....}

b)[tex]\frac{1}{9} < \frac{1}{2n+1} = > 2n+1 < 9 = > 2n < 8 = > n < 4[/tex]  => n∈{0, 1, 2, 3}