a) tr ABC-dreptunghic=>T Pitagora BC^2=Ac^2+AB^2 <=> BC^2=16^2+12^2<=> BC^2=256+144=400, BC=radical din 400 => BC=20cm
b) sinC=cateta opusa/ipotenuza=AB/BC=12/20=3/5
c) Fie AM perp BC=> AM-inaltime corespunzătoare ipotenuzei=> AM=cateta1*cateta2/ipotenuza=AB*AC/BC=12*16/20=9,6cm