Răspuns:
2
Explicație pas cu pas:
[tex]a = {2}^{1} + {2}^{3} + {2}^{5} + .. + {2}^{81} = \\ = 2 \cdot ({2}^{0} + {2}^{2} + {2}^{4} + .. + {2}^{8}) \\[/tex]
[tex]b = {4}^{0} + {4}^{1} + {4}^{2} + .. + {4}^{40} = \\ = {( {2}^{2} )}^{0} + {( {2}^{2} )}^{1} + {( {2}^{2} )}^{2} + .. + {( {2}^{2} )}^{40} \\ = {2}^{0} + {2}^{2} + {2}^{4} + .. + {2}^{8} \\ [/tex]
[tex]a = 2b \implies \frac{a}{b} = \frac{2b}{b} = \bf 2 \\ [/tex]
