Ajutor cu problema 103

a+b+c=345
a+a/4=b+b/2=c+c/5
5a/4=3b/2=6c/5
a/(4/5)=b/(2/3)=c/(5/6)
(a+b+c)/(⁶4/5+¹⁰2/3+⁵5/6)=
345×30/(24+20+25)=
345×30/69=(15×23)×10/23=150
5a/4=150 /:5
a/4=30
a=120
3b/2=150 /:3
b/2=50
b=100
6c/5=150 /:6
c/5=25
c=125
verificare:120+100+125=345