[tex]\it Gf\ are\ dou\breve a\ asimptote\ verticale \ dac\breve a:\\ \\ I)\ x^2-b=0\ admite\ dou\breve a\ r\breve ad\breve acini \Rightarrow b > 0\ \d si\ x^2-b=x^2-(\sqrt b)^2=\\ \\ =(x-\sqrt b)(x+\sqrt b)\\ \\ \\ f(x)=\dfrac{x-a}{(x-\sqrt b)(x+\sqrt b)}\ \ \ \ \ (*)\\ \\ \\ II) \ \ (*) \Rightarrow a\ne\pm\sqrt b \Rightarrow a^2\ne b[/tex]
Răspunsul corct este F.
