Explicație pas cu pas:
[tex]\Big( \frac{4}{3 \sqrt{2} } - \sqrt{0.(2)}\Big) \cdot 3 \sqrt{6} - \Big( \frac{2 \sqrt{3} }{3} - \sqrt{0.(3)} \Big) \cdot \sqrt{6} - \Big( \sqrt{3} - \sqrt{2} \Big) = \\ = \Big( \frac{4 \sqrt{2} }{3 \cdot 2} - \sqrt{ \frac{2}{9} }\Big) \cdot 3 \sqrt{6} - \Big( \frac{2 \sqrt{3} }{3} - \sqrt{ \frac{3}{9} } \Big) \cdot \sqrt{6} - \Big( \sqrt{3} - \sqrt{2} \Big) \\ = \Big( \frac{2 \sqrt{2} }{3} - \frac{ \sqrt{2} }{3} \Big) \cdot 3 \sqrt{6} - \Big( \frac{2 \sqrt{3} }{3} - \frac{ \sqrt{3} }{3} \Big) \cdot \sqrt{6} - \sqrt{3} + \sqrt{2} \\ = \frac{ \sqrt{2} }{3} \cdot 3 \sqrt{6} - \frac{ \sqrt{3} }{3} \cdot \sqrt{6} - \sqrt{3} + \sqrt{2} = 2 \sqrt{3} - \sqrt{2} - \sqrt{3} + \sqrt{2} \\ = \bf \sqrt{3}[/tex]
