Avem linii mijlocii și triunghiuri mediane, deci:
[tex]\it \mathcal{P}_{D EF}=\dfrac{\mathcal{P}_{ABC}}{2}\\ \\ \\ \mathcal{P}_{LGH}=\dfrac{\mathcal{P}_{D EF}}{2}=\dfrac{\dfrac{\mathcal{P}_{ABC}}{2}}{2} =\dfrac{\mathcal{P}_{ABC}}{4} \Rightarrow \dfrac{\mathcal{P}_{LGH}}{\mathcal{P}_{ABC}} =\dfrac{1}{4}[/tex]
